4x^2=1296

Solution for 4x^2=1296 equation:

4x^2=1296

We move all terms to the left:

4x^2-(1296)=0

a = 4; b = 0; c = -1296;
Δ = b2-4ac
Δ = 02-4·4·(-1296)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*4}=\frac{-144}{8}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*4}=\frac{144}{8}
=18
$